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Part B How Far Is The Mass From The Equilibrium Position When The Kinetic Energy Is 1/10 Of The Total

Following are the results obtained in the Below steps; Flow type: Sub-critical (Fr < 1)Momentum function value: 0Conjugate depth: 0.7 m, 0.3 mAlternate depth: 0.98 mMinimum specific energy: 0.53 mCritical depth: 0.67 mMinimum Momentum function: 0.81 mIf there's a jump formed at 1 m depth;Starting depth of jump = d = 1.0 mFinishing depth of jump = 0.7 mJump height = 0.3 mEnergy loss due to jump = 0.81 mLength of jump = 0.81 m.Explanation:Given data; Bottom width (b) = 2.0 m Flow rate (Q) = 4.0 m³/s Flow depth (d) = 1.0 mStep 1: Froude number calculation; Fr = V/√gd Where V = Q/A = Q/bd; here, A = bd √gd Fr = Q/bd / Fr = Q/ √gbd³ Fr = 4.0 / √(9.81 x 2.0 x 1.0³) Fr = 0.90 < 1 Flow type is sub-critical.Step 2: Momentum function calculation;M = (Q/2g) (d²/dy²) [(y + d)²/4]M = (4.0/2×9.81) (0) [(1 + 1)²/4]M = 0The momentum function value is zero.Step 3: Conjugate depth calculation;d1 + d2 = 2d; d1d2 = Q² / (gbd³)Let's take d1 as 0.7 m and calculate d2. d1 + d2 = 2d d2 = 2d – d1 d1d2 = Q² / (…